SQL 学生 课程 分数

建表

create table course (
  id integer primary key,
  name text not null
);

create table student (
  id integer primary key,
  name text not null
);

create table score (
  id integer primary key,
  course_id integer not null,
  student_id integer not null,
  score integer not null
);

准备数据

insert into course values (1, '语文'), (2, '数学'),(3,'外语');
insert into student values (1, '小张'), (2, '小王'), (3, '小马');

insert into score values (1, 1, 1, 80), (2,2,1,90), (3,3,1,70);
insert into score values (4,1,2,70),(5,2,2,90),(6,3,2,80);
insert into score values (7,1,3,80),(8,2,3,60),(9,3,3,70);

查询总分最高的学生分数是多少

先查最高分是多少

select student_id, sum(score)
from score
group by student_id
order by sum(score) desc
limit 1;

但其实可能存在多个学生的总分一样：

select student_id, sum(score)
from score
group by student_id
order by sum(score) desc;

student_id	sum(score)
1	240
2	240
3	210

所以应该是：

select distinct (student_id)
from score 
group by student_id 
having sum(score) = (
  select sum(score)
  from score 
  group by student_id
  order by sum(score) desc
  limit 1
)

在进行连接查询展示出姓名就是：

select s.name, t.score
from student s 
right join  (

	select distinct (student_id), sum(score) score
	from score 
	group by student_id 
	having sum(score) = (
	  select sum(score)
	  from score 
	  group by student_id
	  order by sum(score) desc
	  limit 1
	)

) t on s.id = t.student_id