LinkedHashMap
https://www.bilibili.com/video/BV1JP411379g
package java.util;
……
public class LinkedHashMap<K,V>
extends HashMap<K,V>
implements Map<K,V>
{
……
transient LinkedHashMap.Entry<K,V> head;
transient LinkedHashMap.Entry<K,V> tail;
}
结点左边的“b”是 before 的意思,是指向前驱的引用类型变量;
结点右边的“a”是 after 的意思,是指向后继的引用类型变量;
next 则是按照 hashcode 取模之后存储元素的hash槽的位置;
测试元素添加和取出的顺序
package io.github.jihch;
import java.util.LinkedHashMap;
public class LinkedHashMapTest {
public static void main(String[] args) {
//创建水果集合
LinkedHashMap<String, String> fruits = new LinkedHashMap<>();
//添加水果
fruits.put("apple", "苹果");
fruits.put("banana", "香蕉");
fruits.put("pear", "梨子");
fruits.put("grape", "葡萄");
fruits.put("lemon", "柠檬");
fruits.forEach((k, v) -> {
System.out.printf("key:%s,value:%s\n", k, v);
});
}
}
key:apple,value:苹果
key:banana,value:香蕉
key:pear,value:梨子
key:grape,value:葡萄
key:lemon,value:柠檬
可以发现,元素添加的顺序和取出的顺序一致
测试元素访问的顺序
被访问过的元素排在最后,这里的“被访问过”指的是通过
public V get(Object key) {
Node<K,V> e;
if ((e = getNode(hash(key), key)) == null)
return null;
if (accessOrder)
afterNodeAccess(e);
return e.value;
}
方法获取过;
举个例子,
添加顺序:<"apple","苹果">,<"banana","香蕉">,<"pear","梨子">,<"grape","葡萄">,<"lemon","柠檬">
如果此时访问:<"apple","苹果">
则取出时顺序:<"banana","香蕉">,<"pear","梨子">,<"grape","葡萄">,<"lemon","柠檬">,<"apple","苹果">
import java.util.LinkedHashMap;
public class LinkedHashMapTest {
public static void main(String[] args) {
//创建水果集合
LinkedHashMap<String, String> fruits = new LinkedHashMap<>(16, 0.75f, true);
//添加水果
fruits.put("apple", "苹果");
fruits.put("banana", "香蕉");
fruits.put("pear", "梨子");
fruits.put("grape", "葡萄");
fruits.put("lemon", "柠檬");
System.out.println("访问前:");
fruits.forEach((k, v) -> {
System.out.printf("key:%s,value:%s\n", k, v);
});
fruits.get("apple");
System.out.println("访问后:");
fruits.forEach((k, v) -> {
System.out.printf("key:%s,value:%s\n", k, v);
});
}
}
访问前:
key:apple,value:苹果
key:banana,value:香蕉
key:pear,value:梨子
key:grape,value:葡萄
key:lemon,value:柠檬
访问后:
key:banana,value:香蕉
key:pear,value:梨子
key:grape,value:葡萄
key:lemon,value:柠檬
key:apple,value:苹果
LinkedHashMap 实现 LRU
LRU.java
import java.util.LinkedHashMap;
import java.util.Map;
public class LRU<K, V> {
private static final float loadFactor = 0.75f;
private LinkedHashMap<K, V> map;
private int cacheSize;
public LRU(int cacheSize) {
this.cacheSize = cacheSize;
int capacity = (int)Math.ceil(cacheSize/loadFactor)+1;
map = new LinkedHashMap<K, V> (capacity, loadFactor, true)
{
private static final long serialVersionUID = 1L;
@Override
protected boolean removeEldestEntry(Map.Entry<K, V> eldest) {
return size() > LRU.this.cacheSize;
}
};
}
public synchronized V get(K key) {
return map.get(key);
}
public synchronized void put(K key, V value) {
map.put(key, value);
}
public synchronized void clear() {
map.clear();
}
public String toString() {
StringBuffer sb = new StringBuffer("");
for (Map.Entry<K, V> entry:map.entrySet())
{
sb.append(entry.getValue()+"->");
}
return sb.toString();
}
}
LRUTest.java
public class LRUTest {
public static void main(String[] args) {
LRU<Integer, Integer> lru = new LRU<>(5);
for(int i = 0; i <5; i++) {
lru.put(i, i);
}
System.out.println(lru);
lru.get(3);
System.out.println(lru);
lru.put(5, 5);
System.out.println(lru);
}
}
关键点有两处:
一个是调用 LinkedHashMap 构造传参时给 accessOrder 传值为 true;LinkedHashMap 的有4个构造方法,其中3个构造方法都指定了 accessOrder 的值为 false,表示遍历元素的顺序会和 put 元素的顺序一致;还有一个构造方法接收 accessOrder 传参,accessOrder 值为 true 时,每一次通过 get 方法访问过的元素会放到在遍历元素顺序的末尾;
利用 LinkedHashMap 实现 LRU 的核心是重写 removeEldestEntry 方法,当容量到达上限时,LinkedHashMap 开始按照遍历顺序移除元素,在 accessOrder 为 true 时,队列前面的元素都是相对最近没有 get 过的,就被移除了,而队尾的则都是通过 get 方法访问过的